利用C#生成、执行bat文件

2018/08/17 13:55
阅读数 0

生成bat文件

public void writeBATFile(string fileContent)
        {string filePath = "D:\\test\\testChange.bat";
            if (!File.Exists(filePath))
            {
                FileStream fs1 = new FileStream(filePath, FileMode.Create, FileAccess.Write);//创建写入文件
                StreamWriter sw = new StreamWriter(fs1);
                sw.WriteLine(fileContent);//开始写入值
                sw.Close();
                fs1.Close();
            }
            else
            {
                FileStream fs = new FileStream(filePath, FileMode.Open, FileAccess.Write);
                StreamWriter sr = new StreamWriter(fs);
                sr.WriteLine(fileContent);//开始写入值
                sr.Close();
                fs.Close();
            }
        }

  执行 bat

using System.Diagnostics;

Process proc = null;
            try
            {
                string targetDir = string.Format(@"D:\BizMap\");//this is where testChange.bat lies
                proc = new Process();
                proc.StartInfo.WorkingDirectory = targetDir;
                proc.StartInfo.FileName = "testChange.bat";
                proc.StartInfo.Arguments = string.Format("10");//this is argument
                //proc.StartInfo.CreateNoWindow = true;
                //proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;//这里设置DOS窗口不显示,经实践可行
                proc.Start();
                proc.WaitForExit();
            }
            catch (Exception ex)
            {
                Console.WriteLine("Exception Occurred :{0},{1}", ex.Message, ex.StackTrace.ToString());
            }

  

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