删除链表中重复的结点

原创
2019/09/15 15:44
阅读数 25
public ListNode deleteDuplication(ListNode pHead) {
    if (pHead == null || pHead.next == null)
        return pHead;
    ListNode next = pHead.next;
    if (pHead.val == next.val) {
        while (next != null && pHead.val == next.val)
            next = next.next;
        return deleteDuplication(next);
    } else {
        pHead.next = deleteDuplication(pHead.next);
        return pHead;
    }
}

 

 

1. 首先添加一个头节点,以方便碰到第一个,第二个节点就相同的情况

2.设置 pre ,last 指针, pre指针指向当前确定不重复的那个节点,而last指针相当于工作指针,

/*
 public class ListNode {
    int val;
    ListNode next = null;

    ListNode(int val) {
        this.val = val;
    }
}
*/
public class Solution {
    public ListNode deleteDuplication(ListNode pHead)
    {
if (pHead==null || pHead.next==null){return pHead;}
ListNode Head = new ListNode(0);
Head.next = pHead;
ListNode pre  = Head;
ListNode last = Head.next;
while (last!=null){
    if(last.next!=null && last.val == last.next.val){
        // 找到最后的一个相同节点
        while (last.next!=null && last.val == last.next.val){
            last = last.next;
        }
        pre.next = last.next;
        last = last.next;
    }else{
        pre = pre.next;
        last = last.next;
    }
}
return Head.next;

    }
}

 

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