字梯游戏(C++)

2015/09/08 21:51
阅读数 18

编写一个程序实现字梯游戏。其中,单字母替换的值为1,而单字母的删除或添加的值p>0(p值由使用者指定)。

#include <iostream>
#include <vector>
#include <string>
#include <fstream>
#include <cmath>

using namespace std;

const int INFINTY = 99999;

struct Vertex
{
    vector<int> adj;
    vector<int> weight;
    bool known;
    int dist;
    string name;
    int path;
};

void printPath(int vIndex,vector<Vertex> V)
{
    if(vIndex>=0&&V[vIndex].path>-1)
    {
        printPath(V[vIndex].path,V);
        cout<<" to ";
    }
    cout<<V[vIndex].name;
}

void dijkstra(int sIndex,int tIndex,vector<Vertex> & Vertices)
{
    int smallestDist;
    int smallestVertex;
    Vertex v,s,t;
    int n=Vertices.size();

    Vertices[sIndex].dist=0;
    for(;;)
    {
        smallestDist= INFINITY;
        smallestVertex=-1;

        for(int i=0;i<n;i++)
        {
            if(!Verties[i].known&&Vertices[i].dist<smallestDist)
            {
                smallestDist=Vertices[i].dist;
                smallestVertex=1;
            }
        }

        if(smallestVertex<0||smallestVertex==tIndex)
            break;

        Vertices[smallestVertex].known=true;
        v=Vertices[smallestVertex];

        for(int j=0;j<v.adj.size();j++)
        {
            if(!(Vertices[v.adj[j].known))
            {
                if(v.dist+v.weight[j]<Vertices[v.adj[j].dist)
                {
                    Vertices[v.adj[j]].dist=v.dist+v.weight;
                    Vertices[v.adj[j]].path=smallestVertex;
                }
            }
        }
    }
}

vertor<Vertex> readWords(istream & in)
{
    string oneLine;
    vector<Vertex> v;
    Vertex w;
    while(in>>oneLine)
    {
        w.name=oneLine;
        w.known=false;
        w.path=-1;
        w.dist=INFINITY;
        v.push_back(w);
    }
    return v;
}

int oneCharOff(const string & word1,const string & word2,int p)
{
    string big,small,shrink;
    int cost;
    if(abs((int)(word.length()-word2.length()))>1)
        return 0;
    else if(word1.length()==word2.length())
    {
        int diffs=0;

        for(int i=0;i<word1.length();i++)
            if(word1[i]!=word2[i])
                if(++diffs>1)
                    return 0;
        if(diffs==1)
            return 1;
    }

    if(word2.length()>word1.length())
    {
        big=word2;
        small=word1;
    }
    else
    {
        big=word1;
        small=word2;
    }
    for(int i=0;i<big.length()-1;i++)
    {
        shrink=big.substr(0,1)+big.substr(i+1,big,size()-i-1);
            if(shrink==small)
                return p;
    }
    if(big.substr(0,big.size()-1)==small)
        return p;
    else
        return 0;
}

void fillAdjacencies(vector<Vertex> & words,int p)
{
    int cost;
    for(int i=0;i<words.size();i++)
    {
        for(int j=i+1;j<words.size();j++)
        {
            cost=oneCharOff(words[i].name,words[j].name,p);
            if(cost>0)
            {
                words[i].adj.push_back(j);
                words[i].weight.push_back(cost);
                words[j].adj.push_back(i);
                words[j].weight.push_back(cost);
            }
        }
    }
}

int main()
{
    int p;
    ifstream fin("dict.txt");
    string w1,w2;
    int w1Index,w2Index;
    cout<<"What is the cost of single char deletions: ";
    cin>>p;
    Vector<Vertex> words=readWords(fin);
    do
    {
        cout<<"Enter two words in the dictionary: ";
        cin>>w1>>w2;
        for(w1Index=0;w1Index<words.size()&&words[w1Index].name!=w1;w1Index++)
    }while(w1Index>=words.size()||w2Index>=words.size());
    fillAdjacencies(words,p);
    dijkstra(w1Index,w2Index,words);
    cout<<endl;
    printPath(w2Index,words);
    return 0;
}



感谢您的访问,希望对您有所帮助。

欢迎大家关注或收藏、评论或点赞。


为使本文得到斧正和提问,转载请注明出处:
http://blog.csdn.net/nomasp


版权声明:本文为 NoMasp柯于旺 原创文章,未经许可严禁转载!欢迎访问我的博客:http://blog.csdn.net/nomasp

展开阅读全文
打赏
0
1 收藏
分享
加载中
更多评论
打赏
0 评论
1 收藏
0
分享
返回顶部
顶部