日常开发当中，经常会遇到查询分组数据中最新的一条记录，比如统计当前系统每个人的最新登录记录、外卖系统统计所有买家最新的一次订单记录、图书管理系统借阅者最新借阅书籍的记录等等。今天给大家介绍一下如何实现以上场景的SQL写法，希望对大家能有所帮助！
1、初始化数据表
-- 借阅者表CREATE TABLE `userinfo` (`uid` int(11) NOT NULL AUTO_INCREMENT COMMENT '主键',`uname` varchar(20) NOT NULL COMMENT '姓名',`uage` int(11) NOT NULL COMMENT '年龄',PRIMARY KEY (`uid`) USING BTREE) ENGINE=InnoDB AUTO_INCREMENT=8 DEFAULT CHARSET=utf8 ROW_FORMAT=COMPACT;INSERT INTO `userinfo` VALUES (1, '小明', 20);INSERT INTO `userinfo` VALUES (2, '小张', 30);INSERT INTO `userinfo` VALUES (3, '小李', 28);-- 书籍表CREATE TABLE `bookinfo` (`id` int(11) NOT NULL AUTO_INCREMENT COMMENT '主键',`book_no` varchar(20) NOT NULL COMMENT '书籍编号',`book_name` varchar(20) NOT NULL COMMENT '书籍名称',PRIMARY KEY (`id`) USING BTREE) ENGINE=InnoDB AUTO_INCREMENT=14 DEFAULT CHARSET=utf8 ROW_FORMAT=COMPACT;INSERT INTO `bookinfo` VALUES (1, 'ISBN001', '计算机基础');INSERT INTO `bookinfo` VALUES (2, 'ISBN002', '计算机网络');INSERT INTO `bookinfo` VALUES (3, 'ISBN003', '高等数学');INSERT INTO `bookinfo` VALUES (4, 'ISBN004', '明朝那些事');INSERT INTO `bookinfo` VALUES (5, 'ISBN005', '物理');INSERT INTO `bookinfo` VALUES (13, 'ISBN006', '读者');-- 借阅记录表CREATE TABLE `borrow_record` (`id` int(11) NOT NULL AUTO_INCREMENT COMMENT '主键',`user_id` int(11) NOT NULL COMMENT '用户id',`book_id` int(11) NOT NULL COMMENT '书籍id',`borrowtime` datetime NOT NULL COMMENT '书籍id',PRIMARY KEY (`id`) USING BTREE) ENGINE=InnoDB AUTO_INCREMENT=16 DEFAULT CHARSET=utf8 ROW_FORMAT=COMPACT;INSERT INTO `borrow_record` VALUES (8, 1, 2, '2021-05-01 10:52:00');INSERT INTO `borrow_record` VALUES (9, 2, 4, '2021-07-12 23:32:00');INSERT INTO `borrow_record` VALUES (10, 2, 1, '2021-03-21 09:00:00');INSERT INTO `borrow_record` VALUES (11, 1, 3, '2021-08-11 17:39:00');INSERT INTO `borrow_record` VALUES (12, 1, 5, '2021-09-02 18:12:00');INSERT INTO `borrow_record` VALUES (13, 3, 1, '2021-07-06 12:32:00');INSERT INTO `borrow_record` VALUES (14, 2, 1, '2021-08-09 10:10:00');INSERT INTO `borrow_record` VALUES (15, 4, 3, '2021-04-15 19:45:00'
);
写法1 直接group by 根据userid ，使用聚合函数max取得最近的浏览时间
select a.user_id ,max(c.uname) uname,max(a.borrowtime) borrowtime,max(b.book_name) book_namefrom borrow_record aINNER JOIN bookinfo b on b.id=a.book_idINNER JOIN userinfo c on c.uid=a.user_idGROUP BY a.user_id-- 说明： 这样会存在获取书籍名称错乱的情况，-- 因为使用聚合函数获取的书籍名称，不一定是对应用户-- 最新浏览记录对应的书籍名称
写法2 采用子查询的方式，获取借阅记录表最近的浏览时间作为查询条件
select a.user_id ,c.uname,a.borrowtime,b.book_name book_namefrom borrow_record aINNER JOIN bookinfo b on b.id=a.book_idINNER JOIN userinfo c on c.uid=a.user_idwhere a.borrowtime=(select max(borrowtime)from borrow_record t where t.user_id=a.user_id)-- 说明：可以满足查询效果，不过性能不是最优解
写法3 采用group by + join 性能最高，推荐采用
select a.user_id ,c.uname,a.borrowtime,b.book_name book_namefrom (select t.user_id,max(borrowtime) borrowtimefrom borrow_record t GROUP BY t.user_id) as eINNER JOIN borrow_record a on e.user_id=a.user_idand e.borrowtime=a.borrowtimeINNERJOIN bookinfo b on b.id=a.book_idINNER JOIN userinfo c on c.uid=a.user_id
运行效果如下：
